# What is the amount of heat liberated (in kJ) from 327 g of mercury when it cools from 77.8°C to 12.0°C?

##### 1 Answer

#### Explanation:

For this problem we have to use the specific heat capacity equation:

Based on what you've given me, we have the mass of the sample (m), the specific heat (c), and the change in temperature

(

Since you want the amount of heat liberated to have units of kJ, you need to convert

We can do that by using this relationship:

1000J = 1kJ

Divide 0.139 by 1000 to obtain

Now, all of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).